Given Parallelogram ABCD with AB=(3x-5)cm, BC=(2y-7)cm, Cd=(x+7)cm, AD=(y+3)cm
What is your question?
PQ=3x+15
adasd
To find the values of x and y, we can use the properties of a parallelogram.
In a parallelogram, opposite sides are equal in length. Therefore, AB = CD and BC = AD.
From the given information, we have the following equations:
AB = CD ⟹ 3x - 5 = x + 7
BC = AD ⟹ 2y - 7 = y + 3
Solving these equations will help us determine the values of x and y.
Let's start with the first equation:
3x - 5 = x + 7
To solve for x, we can isolate the x term on one side of the equation.
Subtracting x from both sides:
3x - x - 5 = x - x + 7
2x - 5 = 7
Next, we can isolate the x term by adding 5 to both sides:
2x - 5 + 5 = 7 + 5
2x = 12
Finally, divide by 2 to solve for x:
2x / 2 = 12 / 2
x = 6
Now that we have the value of x, we can substitute it into the second equation to find y:
2y - 7 = y + 3
Subtracting y from both sides:
2y - y - 7 = y - y + 3
y - 7 = 3
Adding 7 to both sides to isolate y:
y - 7 + 7 = 3 + 7
y = 10
So, x = 6 and y = 10.