how much CuSo4•5H2O will precipitate from a aq. soln of CuSO4, 25g dissolved in min amnt of water at 60C then cooled at 0C. Solubility of CuSO4 at 60C in 100 mL H2O is 40 g and in 0C is 15g.
find the water:
60/100=25/x x= 2500/60 ml water
= 41.7 ml
Now, how much can be dissolved at O:
15/100=y/41.7
y=6.25 grams
so amount precipated out is 25-6.25 grams
To determine the amount of CuSO4•5H2O that will precipitate from the given solution, we need to compare the solubility of CuSO4 at 60°C and 0°C with the amount of CuSO4 in the solution after cooling.
First, let's calculate the amount of CuSO4 that can dissolve in 100 mL of water at 60°C and 0°C:
- At 60°C: The solubility of CuSO4 is 40 g in 100 mL of water.
- At 0°C: The solubility of CuSO4 is 15 g in 100 mL of water.
Next, we need to determine the maximum amount of CuSO4 that has dissolved in the given solution at 60°C. We are told that 25 g of CuSO4 is dissolved in the minimum amount of water. Since this amount is less than the maximum solubility at 60°C, we can assume that all of it will dissolve.
Now, we're asked to find out how much CuSO4•5H2O will precipitate when the solution is cooled to 0°C. To do this, we will compare the solubility at 0°C with the original amount dissolved at 60°C.
The difference in solubility between 60°C and 0°C is (40 g - 15 g) = 25 g per 100 mL of water.
Since we dissolved the CuSO4 in the minimum amount of water, we can assume that the final volume is still 100 mL. Therefore, the amount of CuSO4 that will precipitate is 25 g per 100 mL.
Considering that the initial CuSO4 solution was 25 g in total, the mass of CuSO4•5H2O that will precipitate can be calculated using proportions:
(25 g / 100 mL) = (x g / 100 mL)
x = 25 g
Therefore, 25 g of CuSO4•5H2O will precipitate from the solution.