A car traveling at a velocity of 24m/s is accelerated uniformly at a rate of 2m/s^2 for 8 seconds. What is the final velocity?
I will assume that Calculus is part of your integrated science course.
a = 2
then v = 2t + c
at the beginning of the observation, t = 0 , v = 24
so 24 = a(0) + c ----> c = 24
v = 2t + 24
when t = 8
v = 2(8) + 24 = 40 m/s
or, simply ....
for each of the 8 seconds the velocity increases by 2 m/s
that is, there is an increase of 16 m/s
added to the starting velocity of 24 m/s give a velocity of 40 m/s
To find the final velocity of the car, we can use the equation of motion:
final velocity = initial velocity + (acceleration x time)
In this case, the initial velocity of the car is 24 m/s, the acceleration is 2 m/s^2, and the time is 8 seconds.
Plugging these values into the equation:
final velocity = 24 m/s + (2 m/s^2 x 8 s)
Simplifying:
final velocity = 24 m/s + 16 m/s
final velocity = 40 m/s
Therefore, the final velocity of the car is 40 m/s.