Two buses start from same bus stand at 8 a.m. One travel 40km/h and other travel at 50km/h. The second bus reaches the next stop at 10 a.m. How much later will the first bus arrive
30min
the second reaches the next stop at 10am => t= 2 hours
S=V*t= 100km
the first bus arrives ?
t= S/V= 100/40=2.5hours
2o
Raunit
To find out how much later the first bus will arrive, we need to determine the time taken by the first bus to reach the next stop.
We know that the second bus reaches the next stop at 10 a.m. This gives us the time taken by the second bus: 10 a.m. - 8 a.m. = 2 hours.
Now, let's calculate the distance traveled by the second bus. We can use the formula: distance = speed × time.
The speed of the second bus is 50 km/h, and it traveled for 2 hours. So, the distance traveled by the second bus is 50 km/h × 2 hours = 100 km.
Now, let's calculate the time taken by the first bus to cover the same distance of 100 km.
The speed of the first bus is 40 km/h. We can use the same formula: time = distance ÷ speed.
Therefore, the time taken by the first bus is 100 km ÷ 40 km/h = 2.5 hours.
Finally, to find out how much later the first bus will arrive, we subtract the time taken by the second bus from the time taken by the first bus.
2.5 hours - 2 hours = 0.5 hours.
Therefore, the first bus will arrive 0.5 hours or 30 minutes later than the second bus.