4.8g of magnesium react was completely burned in oxygen and magnesiumoxide was produced. what is the mass of magnesium produced?
To determine the mass of magnesium produced, we need to use the balanced chemical equation for the reaction between magnesium and oxygen that forms magnesium oxide. The balanced chemical equation is as follows:
2Mg + O₂ → 2MgO
From the equation, we can see that two magnesium atoms react with one oxygen molecule to form two molecules of magnesium oxide.
Now, let's calculate the molar mass of magnesium (Mg) and magnesium oxide (MgO):
- Molar mass of Mg = 24.31 g/mol
- Molar mass of MgO = 40.31 g/mol (24.31 g/mol for Mg + 16.00 g/mol for O)
Since the molar mass of magnesium is less than that of magnesium oxide, we know that the mass of magnesium will be less than the mass of magnesium oxide.
Given that the mass of magnesium oxide produced is 4.8 g, we can calculate the amount of magnesium that reacted using the molar ratio from the balanced chemical equation:
(2 moles of MgO) / (2 moles of Mg) = (molar mass of MgO) / (molar mass of Mg)
Let's do the calculation:
4.8 g MgO × (2 moles of Mg) / (40.31 g MgO) = 0.238 moles of Mg
Finally, we can convert the moles of magnesium to grams using the molar mass of magnesium:
0.238 moles of Mg × 24.31 g/mol = 5.80 g of Mg
Therefore, the mass of magnesium produced is approximately 5.80 grams.