find f(-3) for f(x)= 3x-x^2
f(-3)=0
f(-3)=18
f(-3)=-18<---
f(-3)=-15
What is the range of f(x)?
f(x)=|x+1|
All real numbers greater than 0
All real numbers greater than -1
All real numbers greater than or equal to 0<-
All real numbers greater than or equal to -1
f(x)=4x^2-2x+3 ; g(x)=2x^3+4x-7
What is the value of (f-g)(2)?
6
10
5
8<-
first two correct.
(f-g)(x)=f(x)-g(x)
16-4+3 -16-8+7
-12+10=-2
check that.
10? Okay im lost.
3rd one:
f(x)=4x^2-2x+3 ; g(x)=2x^3+4x-7
(f-g)(x) = 2x^2 - 6x + 10
(f-g)(2) = 8 - 12 + 10 = 6
forget my previous post, did not notice the x^3
f(x)=4x^2-2x+3 ; g(x)=2x^3+4x-7
(f-g)(x) = 4x^2 - 6x + 10 - 2x^3
(f-g)(2) = 16 - 12 + 10 - 16
= -2
bobpursley was correct
Thanks guys!
To find f(-3) for the given function f(x) = 3x - x^2, substitute -3 for x in the function and evaluate the expression.
f(-3) = 3(-3) - (-3)^2
= -9 - 9
= -18
Therefore, f(-3) = -18.
To determine the range of the function f(x) = |x+1|, consider the possible outputs (or y-values) of the function. The absolute value of any number is always greater than or equal to 0. Therefore, the range of f(x) is all real numbers greater than or equal to 0.
For the expression (f - g)(2), the operation is subtraction (f minus g), and we need to evaluate it at x = 2.
Given f(x) = 4x^2 - 2x + 3 and g(x) = 2x^3 + 4x - 7, substitute x = 2 into both functions and subtract the results:
(f - g)(2) = f(2) - g(2)
= (4(2)^2 - 2(2) + 3) - (2(2)^3 + 4(2) - 7)
= (16 - 4 + 3) - (16 + 8 - 7)
= (15) - (17)
= -2
Therefore, the value of (f - g)(2) is -2.