a company owns only cars and trucks. The sum of the cars and trucks owned by the company is 60. One sixh of the red and one half of the trucks are red. If there are twice as many red trucks as red cars, how many cars are not red?
A- 6
B- 12
C-24
D-30
C- Its not there
I think its D, show process please. thank you
is it really "1/6 of the red"?
c=cars
t=trucks
rt=red trucks
rc=red cars
t+c=60
60-t=c
rt=2rc
since red trucks are twice as many as red cars
but
rt= 1/2 t
rc= 1/6 c
1/2 t=2(1/6 x c)
1/2 t =2(1/6 x (60-t))
1/2 t = 1/3 (60-t)
1/2 t = 20- 1/3 t
1/2 t + 1/3 t= 20
5/6 t = 20
t= 24 trucks
so...
60-t= c
c= 36 cars
1/6 of cars are red so..
36 cars x 1/6 = 6 cars are red
36-6 = 30 cars are not red..
checK: red trucks are twice as many as red cars...24/2=2x6 red cars
12=12
the answer is d
To solve this problem, let's break it down step by step:
Let's assume the number of red cars is 'x'.
According to the problem, the number of red trucks is twice the number of red cars, so the number of red trucks would be '2x'.
Given that one-sixth of the red vehicles are cars, we can express this as:
(x) = (1/6) * (x + 2x)
=> six times the number of red cars equals the sum of red cars and red trucks.
Now, let's calculate the total number of vehicles:
Total vehicles = number of cars + number of trucks
=> 60 = (x) + (2x)
=> 60 = 3x
=> x = 60/3
=> x = 20
So, there are 20 red cars and 2x = 2 * 20 = 40 red trucks.
Now, let's find the number of cars that are not red:
Number of cars that are not red = Total number of cars - Number of red cars
= 60 - 20
= 40
Hence, the correct answer is D- 30 cars are not red.