Robert wants to buy wrapping paper to cover a square-shapedpainting. To determine the size of the wrapping paper needed for the painting, he adds 9 inches to each side of the painting.Robert picks out wrapping paper with a perimeter of 120 inches to wrap the square-shaped painting.
The side length of the wrapping paper is inches, and the side length of the painting is inches.
Here is the correct question guys:
Robert wants to buy wrapping paper to cover a square-shaped painting. To determine the size of the wrapping paper needed for the painting, he adds 9 inches to each side of the painting. Robert picks out wrapping paper with a perimeter of 120 inches to wrap the square-shaped painting.
The side length of the wrapping paper is
inches, and the side length of the painting is
inches.
To determine the side length of the wrapping paper, we can use the formula for the perimeter of a square: P = 4s, where P is the perimeter and s is the side length of the square.
In this case, the perimeter of the wrapping paper is given as 120 inches. So we can set up the equation as follows:
120 = 4s
Now, we can solve for s by dividing both sides of the equation by 4:
s = 120/4 = 30 inches
Therefore, the side length of the wrapping paper is 30 inches.
To find the side length of the painting, we need to subtract 9 inches from each side of the wrapping paper, as given in the problem.
So, the side length of the painting would be:
30 - 9 = 21 inches
Therefore, the side length of the painting is 21 inches.
people are not helpful
It would help if you proofread your questions before you posted them.
What are the side lengths and what is your question?