eli is twice as old as josh, and ben is six years older than josh. the sum of their age is 50.how old is each person?
Chase is 5 years older than Naomi. In 7 years the sum of their ages will be 71. How old is Chase now
J= x; E= 2x;B=x+6
x+2x+x+6=50
4x+6=50
4x=50-6
4x=44
4x/4=44/4
x=11
J=11;E=2(11)=22;B=11+6=17
Let's start by assigning variables to each person's age.
Let's say Eli's age is E, Josh's age is J, and Ben's age is B.
According to the given information:
- Eli is twice as old as Josh, so E = 2J.
- Ben is six years older than Josh, so B = J + 6.
- The sum of their ages is 50, so E + J + B = 50.
Now, we can use these equations to solve for each person's age.
Substituting E = 2J and B = J + 6 in the sum equation, we have:
(2J) + J + (J + 6) = 50.
Combining like terms:
4J + 6 = 50.
Subtracting 6 from both sides:
4J = 44.
Dividing both sides by 4:
J = 11.
Now, we can find the age of each person:
E = 2J = 2(11) = 22.
B = J + 6 = 11 + 6 = 17.
Therefore, Eli is 22 years old, Josh is 11 years old, and Ben is 17 years old.
To solve this problem, we'll use algebraic equations to represent the information given.
Let's say the age of Josh is x.
According to the problem, Eli is twice as old as Josh, so Eli's age is 2x.
And Ben is six years older than Josh, so Ben's age is x + 6.
We're also given that the sum of their ages is 50, so we can write the equation:
x + 2x + (x + 6) = 50
Now, we'll solve this equation to find the value of x, which represents Josh's age.