net ionic equation of 3Cr(c2h3o2)2 +2(nh4)3(po4)--Cr3(po4)2+6Nh4(c2h3o2)with states
To write the net ionic equation, we need to first write the balanced chemical equation and then determine the spectator ions that do not participate in the reaction. The net ionic equation only includes the ions and compounds that are directly involved in the reaction.
Here is the balanced chemical equation for the given reaction with states of matter:
3 Cr(C2H3O2)2 (aq) + 2 (NH4)3PO4 (aq) → Cr3(PO4)2 (s) + 6 NH4C2H3O2 (aq)
To write the net ionic equation, we need to first write the equation in ionic form (separating dissociated ions):
3 Cr2+ (aq) + 6 C2H3O2- (aq) + 6 NH4+ (aq) + 2 PO43- (aq) → Cr3(PO4)2 (s) + 6 NH4+ (aq) + 6 C2H3O2- (aq)
Next, we identify the spectator ions, which are the ions that appear on both sides of the reaction unchanged. In this case, the NH4+ ions and C2H3O2- ions are the spectator ions because they are present on both sides of the reaction.
Therefore, the net ionic equation can be simplified as:
3 Cr2+ (aq) + 2 PO43- (aq) → Cr3(PO4)2 (s)
The net ionic equation only includes the ions directly involved in the reaction, which are the chromium (Cr2+) and phosphate (PO43-) ions.
Note that the NH4+ and C2H3O2- ions are not included in the net ionic equation since they do not participate in the reaction and are considered as spectator ions.