I need help writing the net ionic equation for 3Cr(c2h3o2)2 +2(nh4)3(po4)--Cr3(po4)2+6Nh4(c2h3o2)with states
To write the net ionic equation, we first need to write out the complete balanced chemical equation, including states of matter.
The given equation is:
3Cr(C2H3O2)2 + 2(NH4)3PO4 -- Cr3(PO4)2 + 6NH4(C2H3O2)
To determine the states of matter, we'll need to consult a solubility chart.
Based on general solubility rules, we know that most nitrate (NO3-) salts are soluble, most acetate (C2H3O2-) salts are soluble, and most ammonium (NH4+) salts are soluble. Phosphate (PO4^3-) salts, on the other hand, are often insoluble, except for those of Group 1A cations and ammonium (NH4+).
Using this information, we can assign the states of matter:
3Cr(C2H3O2)2 (aq) + 2(NH4)3PO4 (aq) -- Cr3(PO4)2 (s) + 6NH4(C2H3O2) (aq)
Now, to write the net ionic equation, we first need to identify the ions present in each solution.
In the first reactant, Cr(C2H3O2)2 dissociates into Cr^2+ and 2C2H3O2-.
In the second reactant, 3(NH4)3PO4 dissociates into 6NH4+ and 2PO4^3-.
In the final equation, Cr3(PO4)2 stays as a solid, and 6NH4(C2H3O2) dissociates into 6NH4+ and 6C2H3O2-.
The net ionic equation only includes the species that are involved in the reaction. We can remove the spectator ions (ions that appear on both sides of the equation unchanged).
From the above reactions, the net ionic equation is:
Cr^2+ + 2PO4^3- -- Cr3(PO4)2
In summary, the net ionic equation for 3Cr(C2H3O2)2 + 2(NH4)3PO4 -- Cr3(PO4)2 + 6NH4(C2H3O2) with states is:
Cr^2+ + 2PO4^3- -- Cr3(PO4)2