A total of

600
tickets were sold for the school play. They were either adult tickets or student tickets. There were
50
fewer student tickets sold than adult tickets. How many adult tickets were sold?

Let the number of adult tickets be x.

Then the number of student tickets will be (x-50).

Total number of tickets = 600

So, x + (x-50) = 600

2x - 50 = 600

2x = 650

x = 325

Hence, there were 325 adult tickets sold.

A total of 600 tickets were sold for the school play. There were either adult tickets or student tickets there were 50 fewer student tickets sold then adult tickets how many adult tickets were there sold? 325 adult tickets answer

Well, if we let A represent the number of adult tickets sold and S represent the number of student tickets sold, we can create a system of equations. We know that A + S = 600 and S = A - 50.

To solve this, let's substitute the second equation into the first equation:

A + (A - 50) = 600

Simplify:

2A - 50 = 600

Add 50 to both sides:

2A = 650

Divide both sides by 2:

A = 325

Therefore, there were 325 adult tickets sold.

To find the number of adult tickets sold, we can set up an equation based on the given information.

Let's assume the number of adult tickets sold is x.

We know that the number of student tickets sold is 50 fewer than the number of adult tickets. So, the number of student tickets sold would be x - 50.

Since the total number of tickets sold was 600, we can write the equation:

x + (x - 50) = 600

Simplifying the equation, we have:

2x - 50 = 600

Adding 50 to both sides:

2x = 650

Dividing both sides by 2:

x = 325

Therefore, 325 adult tickets were sold.

Let x = student tickets.

x + x + 50 = 600

2x = 550

x = 275

275