A frog jumps at 0.6 m/s at an angle of 20 degrees and lands on a level surface. How far does the frog jump?
Vo = 0.6m/s[20o].
Range = Vo^2*sin(2A)/g.
Range = 0.6^2*sin(40)/9.8 =
To calculate the distance the frog jumps, we can use the equations of projectile motion. The horizontal distance traveled, also known as the range (R), can be determined using the following equation:
R = (v^2 * sin(2θ)) / g
Where:
- v is the initial velocity of the frog (0.6 m/s)
- θ is the launch angle (20 degrees)
- g is the acceleration due to gravity (approximately 9.8 m/s^2)
First, let's convert the launch angle from degrees to radians, as the trigonometric functions in most programming languages work with radians. To convert degrees to radians, use the following equation:
radians = degrees * (π/180)
For our case, the launch angle in radians (θ_radians) will be:
θ_radians = 20 * (π/180)
Now we can plug in the values into the range equation:
R = (0.6^2 * sin(2 * θ_radians)) / 9.8
Note: "^" denotes exponentiation.
Let's calculate the value of R.