Several forces are applied to an object. If the object 40 m along the horizontal, and if one of the forces is a constant 5.0 N in the opposite direction, then what is the worst done on the object by that force?
To find the work done on the object by the force, we need to use the formula:
Work = Force x Distance x cosθ
In this case, the force is 5.0 N and the distance is 40 m. The angle θ is not given, but since the force is opposite to the direction of motion (horizontal), the angle between the force and the displacement is 180 degrees (or π radians).
Now we can calculate the work done:
Work = 5.0 N x 40 m x cos(180°)
Work = 5.0 N x 40 m x (-1)
Work = -200.0 N·m
Therefore, the work done on the object by the force is -200.0 N·m (or -200 Joules). The negative sign indicates that the work is done in the opposite direction of displacement, which implies that the force acts against the motion.
To calculate the work done on the object, we need to use the formula:
Work = Force x Distance x cos(θ)
where:
- Force is the magnitude of the force applied to the object
- Distance is the distance over which the force is applied
- θ is the angle between the direction of the force and the direction of motion of the object
In this case, the force is 5.0 N, and it is applied in the opposite direction. Since the force is applied opposite to the direction of motion, the angle θ will be 180 degrees.
So, the formula becomes:
Work = 5.0 N x 40 m x cos(180°)
Now, let's calculate the work done:
Work = 5.0 N x 40 m x (-1)
Work = -200 N·m
The work done on the object by the force of 5.0 N in the opposite direction is -200 N·m. The negative sign indicates that the work done is in the opposite direction of the displacement, indicating that the force is acting against the motion of the object.