Zn(s)+HCl(aq)--> ZnCl2(aq)+H2(g)

net ionic??

To write the net ionic equation, you need to first write the balanced molecular equation and then determine the soluble compounds and write their dissociated ions. Here's how you can do it for the given reaction:

Step 1: Write the balanced molecular equation:
Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)

Step 2: Determine the soluble compounds:
From the solubility rules, we know that most chloride (Cl-) salts are soluble, including ZnCl2.

Step 3: Write the dissociated ions:
Zn(s) + 2H+(aq) + 2Cl-(aq) → Zn2+(aq) + 2Cl-(aq) + H2(g)

Step 4: Cancel out the spectator ions:
The net ionic equation is obtained by canceling out the spectator ions, which are the ions that appear on both sides of the equation. In this case, the Cl- ions appear on both sides and thus can be canceled out.

Net ionic equation:
Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g)

So, the net ionic equation for the reaction Zn(s) + HCl(aq) → ZnCl2(aq) + H2(g) is Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g).