Triangle ABC has a right angle at C. The bisector of an exterior angle at B intersects line AC at D. If AB=13 and BC=5, what is the length of segment BD?

BD divides AC in the ratio 5:13. You can use that and the law of cosines to find BD

Or, knowing all the angles in ABD, use the law of sines.

To find the length of segment BD, we will first use the Pythagorean theorem to find the length of segment AC.

Since triangle ABC is a right triangle with a right angle at C, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In this case, AB is one of the legs of the right triangle, and BC is the other leg. Let's calculate the length of AC using the Pythagorean theorem:

AC² = AB² + BC²
AC² = 13² + 5²
AC² = 169 + 25
AC² = 194

Taking the square root of both sides, we have:

AC = √194

Now, let's find the length of segment BD. The bisector of an exterior angle at B intersects line AC at D. Since the bisector of an exterior angle divides the opposite side of a triangle into two segments proportional to the adjacent sides, we can set up a proportion to find the length of segment BD.

Let's call the length of BD as x:

BD/DC = AB/AC

Substituting the given values:

x/(AC - x) = AB/AC
x/(√194 - x) = 13/√194

Now, let's cross-multiply and solve for x:

x * √194 = (√194 - x) * 13
x * √194 = 13 * √194 - 13x

Bringing all terms with x to one side:

x * √194 + 13x = 13 * √194
(√194 + 13) * x = 13 * √194

Dividing both sides by (√194 + 13):

x = (13 * √194) / (√194 + 13)

Simplifying this expression, we find:

x ≈ 8.04

Therefore, the length of segment BD is approximately 8.04.

To find the length of segment BD, we can apply the angle bisector theorem.

The angle bisector theorem states that if a line bisects an angle of a triangle, it divides the opposite side into two segments that are proportional to the other two sides of the triangle.

In this case, the exterior angle at B is the same as the interior angle at B in triangle ABC. Let's call this angle x.

Since triangle ABC is a right triangle, we know that angle B is 90 degrees. Therefore, the exterior angle at B is 180 degrees - 90 degrees = 90 degrees.

The angle bisector of the exterior angle at B intersects line AC at point D. Let's call the length of segment BD as b and the length of segment AD as a.

According to the angle bisector theorem, we have the following proportion:

BD/AD = BC/AC

Substituting the given values, we get:

b/(a+13) = 5/13

Cross-multiplying, we have:

5b = 5(a+13)

5b = 5a + 65

Subtracting 5a from both sides, we get:

5b - 5a = 65

Now, we can apply the fact that the bisector of an exterior angle at B intersects line AC at point D. This means that angle BDA is equal to half of the measure of the exterior angle at B.

Since the exterior angle at B is 90 degrees, angle BDA is 90/2 = 45 degrees.

Now, we have a right triangle BDA with angle BDA equal to 45 degrees.

To find the length of segment BD, we can use the sine function.

sin(angle BDA) = BD/AB

Substituting the given values, we get:

sin(45) = b/13

Simplifying, we have:

1/√2 = b/13

Cross-multiplying, we get:

b = 13/√2

To find an approximation of the length of segment BD, we can use a calculator.

Calculating, we get:

b ≈ 9.19

Therefore, the length of segment BD is approximately 9.19 units.