If g(t)= 1/t-2-1,
how to solve g(t)=0 ...?
Please teach me..!
you fill t with 0
so 0-2-1=-3
if it said find g(t)=6
1/6-2-1=-17/6
I disagree with what Christos did
it said solve g(t) = 0 , not find g(0)
First of all I am sure you meant:
g(t) = 1/(t-2) - 1
so if g(t) = 0,
1/(t-2) - 1 = 0
1/(t-2) = 1
t - 2 = 1
t = 2
It isn't t=3 ..?
Thanks for answers!!
To solve the equation g(t) = 0, which is 1/(t - 2) - 1 = 0, we can follow these steps:
Step 1: Simplify the equation:
1/(t - 2) - 1 = 0
Step 2: Get rid of the fraction by multiplying all terms by (t - 2):
(t - 2) * 1/(t - 2) - (t - 2) * 1 = 0 * (t - 2)
1 - (t - 2) = 0
Step 3: Distribute the negative sign:
1 - t + 2 = 0
Step 4: Combine like terms:
3 - t = 0
Step 5: Isolate the variable t by subtracting 3 from both sides:
-t = -3
Step 6: Solve for t by multiplying both sides by -1:
t = 3
So, the solution to the equation g(t) = 0 is t = 3.