Gold has a latent heat fusion of 64.5 J/g. How much energy is required to melt 20.0 g of gold?
1290
dq = mass Au x heat fusion
To find out the amount of energy required to melt 20.0 g of gold, we can use the formula:
Energy = mass * latent heat of fusion
Given that the latent heat of fusion of gold is 64.5 J/g, and the mass of gold is 20.0 g, we can substitute these values into the formula:
Energy = 20.0 g * 64.5 J/g
Now, we can perform the multiplication:
Energy = 1290 J
Therefore, 1290 J of energy is required to melt 20.0 g of gold.
To find the amount of energy required to melt 20.0 g of gold, you can use the formula:
Energy = mass × latent heat fusion
Given:
Mass = 20.0 g (grams)
Latent heat fusion of gold = 64.5 J/g (joules per gram)
Now, plug in the values into the formula:
Energy = 20.0 g × 64.5 J/g
Multiply the mass (20.0 g) by the latent heat fusion (64.5 J/g):
Energy = 1290 J (joules)
Therefore, it requires 1290 joules of energy to melt 20.0 grams of gold.