a particle is projected horizontally at 15m/s from a height of 20m calculate the horizontal distance covered by the particle just before hitting the ground (g=10m/s*2)
20 = (1/2)10 t^2
solve for t = 2 seconds
d = 15 t =15*2 = 30 m
30m
An object is projected with a velocity of 100m/s from the ground level at an angle tera to the vertical.if the total time of flight of the projectiles is 10s,calculate teta
Answer: 30m
Step-by-Step Help:
1. We know that an object is projected from and with a velocity of 100m/s from the ground level at an angle of tera to the vertical level/direction
2. We also know that the total time of the flight of projectiles is at 10 seconds/m
3. From there, we have the calculate using algebra, physics, and chemistry together: we have the calculate the tera.
4. Result: 30m
I hope this worked out well, and ask me for more questions if needed! :) ~ and remember physics is easy, just calculate it like a daily life basis, and solve mentally or even better --- physically.
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Why did the particle bring a map to its flight? Because it wanted to make sure it didn't get lost on its horizontal journey!
Now, let's calculate the horizontal distance covered by our little eager particle. We know that the initial vertical velocity is zero because it's projected horizontally. The time it takes to hit the ground can be found using the formula:
t = sqrt(2h / g)
Where:
h = initial height = 20m
g = acceleration due to gravity = 10m/s^2
t = sqrt(2 * 20 / 10) = sqrt(4) = 2s
Since this is a horizontal projection, we know that the horizontal distance traveled is equal to the initial horizontal velocity multiplied by the time taken.
So, Distance = Horizontal Velocity * Time = 15m/s * 2s = 30 meters.
Voila! The particle covered a horizontal distance of 30 meters before hitting the ground.
To calculate the horizontal distance covered by the particle just before hitting the ground, you can use the equation of motion:
distance = velocity × time
First, let's find the time it takes for the particle to hit the ground. We know that the initial vertical velocity (Vy) is 0 m/s, and the acceleration due to gravity (g) is -10 m/s^2 (negative because it acts downwards).
Using the second equation of motion:
Vy = Vy0 + (g × t)
where Vy0 is the initial vertical velocity, g is the acceleration due to gravity, and t is the time.
0 = 0 + (-10 × t)
0 = -10t
t = 0 seconds
Here we find that the particle takes 0 seconds to reach the ground horizontally after being projected horizontally.
Now, let's calculate the horizontal distance covered by the particle. We know that the horizontal velocity (Vx) is 15 m/s.
Using the first equation of motion:
distance = velocity × time
distance = 15 m/s × 0 seconds
distance = 0 meters
Therefore, the horizontal distance covered by the particle just before hitting the ground is 0 meters.