My number has 1 hundred and 1 thousand. It has double the number of tens as ones. What could my number be?

1100

1121
1142
1163
1184

1100

To find the number that satisfies the given conditions, we can break it down into its components and solve step by step.

Let's say the number has the form ABCD, where A represents the thousands digit, B represents the hundreds digit, C represents the tens digit, and D represents the ones digit.

Given that the number has 1 hundred and 1 thousand, it means that B = 1 and A = 1.

Now, let's focus on the second condition: "It has double the number of tens as ones." We can rewrite this condition as C = 2D.

Putting together the information we have so far, the number can be represented as 1ABD.

Substituting B = 1 and A = 1, we get 110D.

Now, let's consider the possible values for D. The range of D values is typically from 0 to 9.

If we try each of these values, we find that the only solution that satisfies the condition C = 2D is when D = 7. In this case, C = 2 * 7 = 14.

So, the possible number that meets both conditions is 1177.