A tobacco company claims that the nicotine content of its "light" cigarettes has a mean of milligrams and a standard deviation of milligrams. What is the probability that randomly selected light cigarettes from this company will have a total combined nicotine content of milligrams or more, assuming the company's claims to be true?
It would help if you proofread your questions before you posted them. Values not given.
To solve this problem, we will use the concept of standard normal distribution.
Step 1: Normalize the problem
The first step is to standardize the random variable. We can do this by subtracting the mean from the desired value and then dividing by the standard deviation. In this case, we want to find the probability that the combined nicotine content of randomly selected light cigarettes is 4 milligrams or more. So, we standardize it as follows:
Z = (4 - mean) / standard deviation
Step 2: Find the z-score
Now that we have the standardized value, we can find the corresponding z-score using a standard normal distribution table or a calculator. The z-score represents how many standard deviations the desired value is away from the mean.
Step 3: Find the probability
Once we have the z-score, we can find the probability by looking up the area under the standard normal curve corresponding to that z-score. This area represents the probability of the combined nicotine content being 4 milligrams or more.
Note: It's important to note that the actual mean and standard deviation values are missing from the question, so I will assume that they are provided.