Using the balanced chemical equation, the number of moles of oxygen gas needed
to react with 2.5 moles of Mg is __________.
2 Mg + O2 → 2 MgO
I see a lot of question here with no effort on your part. I worked the last two. I can help with the others but HELP is the key word.
To determine the number of moles of oxygen gas needed to react with 2.5 moles of Mg, we need to use the stoichiometric coefficients from the balanced chemical equation.
From the equation: 2 Mg + O2 → 2 MgO
The stoichiometric coefficient in front of O2 is 1. This means that for every 1 mole of O2, we need 2 moles of Mg to react completely.
Since we are given 2.5 moles of Mg, we can set up a ratio:
2 moles of Mg / 1 mole of O2 = 2.5 moles of Mg / x moles of O2
Solving for x, we can cross-multiply:
2 * x = 2.5 * 1
2x = 2.5
x = 2.5 / 2
x = 1.25
Therefore, the number of moles of oxygen gas needed to react with 2.5 moles of Mg is 1.25 moles.