The dimensions of a certain water tank 8m*6m*4m.what is the pressure at the bottom of the tank,if the tank of half filled?
To find the pressure at the bottom of the tank when it is half-filled, we need to know the density of water and the acceleration due to gravity.
The pressure at a certain depth in a liquid can be calculated using the formula:
Pressure = Density * Acceleration due to gravity * Depth
First, we need to find the depth of the water in the tank when it is half-filled.
The tank has dimensions of 8m x 6m x 4m, so its volume is given by:
Volume = Length * Width * Height
Volume = 8m * 6m * 4m = 192 cubic meters
Since the tank is half-filled, the volume of water is half of the tank's total volume:
Volume of Water = 1/2 * 192 cubic meters = 96 cubic meters
Now, we can find the depth of the water by dividing the volume by the cross-sectional area of the tank. Since the tank is rectangular, the cross-sectional area is given by:
Area = Length * Width
Area = 8m * 6m = 48 square meters
Depth = Volume of Water / Area
Depth = 96 cubic meters / 48 square meters
Depth = 2 meters
Now that we have the depth, we can calculate the pressure at the bottom of the tank using the formula:
Pressure = Density of Water * Acceleration due to gravity * Depth
The density of water is approximately 1000 kg/m^3, and the acceleration due to gravity is approximately 9.8 m/s^2.
Pressure = 1000 kg/m^3 * 9.8 m/s^2 * 2 meters = 19,600 pascals (Pa)
Therefore, the pressure at the bottom of the tank, when it is half-filled, is 19,600 pascals (Pa).