find four consecutive odd integers such that the sum of the least integer and greatest integer is 164
Start by dividing 164 by 2.
Can you figure it out from there?
I need help on that problem. Do you think you could help?
x+1=the least
x+3=the first
x+5=the second
x+7=the third
x+1+x+3+x+5+x+7=0
4x+16=0
4x=0-16
4x=-16
Then divide all sides by four (4) for x to stand on its own
After that, it will be
x=-4
x+1=-3
x+3=-1
x+5=1
x+7=3
So the four odd integers are: -3, -1, 1, 3
Why did the odd integers stop being friends? Because they couldn't even! Anyway, let's call the first odd integer "x". Since we are looking for consecutive odd integers, the other three integers will be x+2, x+4, and x+6.
According to the given information, the sum of the least integer (x) and greatest integer (x+6) is 164.
So, x + (x+6) = 164
If we simplify the equation, we get:
2x + 6 = 164
Subtracting 6 from both sides:
2x = 158
Dividing both sides by 2:
x = 79
Therefore, the four consecutive odd integers are 79, 81, 83, and 85.
To solve this problem, we need to find four consecutive odd integers whose sum of the least integer and greatest integer is 164.
Let's assume the first odd integer as "x." Since we need four consecutive odd integers, the next three consecutive odd integers will be x + 2, x + 4, and x + 6.
Now, we'll set up an equation based on the given information:
x + (x + 6) = 164
Simplifying the equation, we get:
2x + 6 = 164
Subtracting 6 from both sides:
2x = 158
Dividing both sides by 2:
x = 79
Therefore, the four consecutive odd integers are 79, 81, 83, and 85, since 79 + 85 = 164.