The decomposition of 3.32 g CaCO3 results in an actual yield of 1.24 g of CaO. What is the percent yield of calcium oxide for this reaction?
CaCO3(s) → CaO(s) + CO2(g)
To find the percent yield, we need to compare the actual yield of calcium oxide (CaO) to the theoretical yield of CaO. The theoretical yield is the maximum amount of product that can be obtained based on the balanced chemical equation.
Let's start by calculating the theoretical yield of CaO.
1. Determine the molar mass of CaCO3:
The molar mass of CaCO3 = the atomic mass of calcium (Ca) + the atomic mass of carbon (C) + 3 times the atomic mass of oxygen (O)
The atomic mass of calcium (Ca) is 40.08 g/mol
The atomic mass of carbon (C) is 12.01 g/mol
The atomic mass of oxygen (O) is 16.00 g/mol
Therefore, the molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + (3 * 16.00 g/mol)
= 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
= 100.09 g/mol
2. Use the molar mass of CaCO3 to convert grams of CaCO3 to moles:
Moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
Given that the mass of CaCO3 is 3.32 g:
Moles of CaCO3 = 3.32 g / 100.09 g/mol
= 0.0332 mol
3. Use the stoichiometry of the balanced chemical equation to find the mole ratio between CaCO3 and CaO:
From the balanced equation: 1 mole of CaCO3 produces 1 mole of CaO
Therefore, the number of moles of CaO produced is also 0.0332 mol.
4. Calculate the theoretical yield of CaO:
Theoretical yield of CaO = Moles of CaO * Molar mass of CaO
The molar mass of CaO is 56.08 g/mol:
Theoretical yield of CaO = 0.0332 mol * 56.08 g/mol
= 1.860 g
Now let's calculate the percent yield.
Percent yield = (Actual yield / Theoretical yield) * 100
Given that the actual yield is 1.24 g:
Percent yield = (1.24 g / 1.860 g) * 100
= 66.67%
Therefore, the percent yield of calcium oxide (CaO) for this reaction is 66.67%.
First determine theoretical yield (TY). The actual yield (AY) is given as 1.24g.
mols CaCO3 = grams/molar mass = ?
Look at the equation. You get 1 mol CaO for every 1 mol CaCO3; therefore, mols CaCO3 from above will give you that many mols CaO.
Convert mols CaO to grams. g = mols CaO x molar mass CaO. That is the TY.
Then %yield = (AY/TY)*100 = ?