-1/2 + 1/3=
A.-1/6
B.-1/3
C.2/3
D.1/6
-3 5/1 + (-6 1/2)=
A.-3 2/7
B.-3 7/10
C.-9 2/7
D.-9 7/10
5/8 -(-2/8)=
A.-3/8
B.-7/8
C.3/8
D.7/8
-9/10 - 2/5=
A.-1 3/10
B.-1 1/10
C.-7/10
D.-5/10
6 3/5-(-2 1/5)
A.-8 2/5
B.-4 2/5
C.4 2/5
D.8 2/5
SOMEONE PLEASE HELP ME!!!
I need someone to check my answer these are mine
A.
D.
D.
A.
D.
1 / 2 = 1 * 3 / 2 * 3 = 3 / 6
- 1 / 2 = - 3 / 6
1 / 3 = 1 * 2 / 3 * 2 = 2 / 6
- 1 / 2 + 1 / 3 = - 3 / 6 + 2 / 6 = - 1 / 6
Answer A
I don't know what3 5/1 nean.
5 / 8 - ( - 2 / 8 ) =
5 / 8 + 2 / 8 )= 7 / 8
Answer D
2 / 5 = 2 * 2 / 5 * 2 = 4 / 10
- 9 / 10 - 2 / 5 =
- 9 / 10 - 4 10 =
- 13 / 10 =
- [ ( 10 + 3 ) / 10 ] =
- ( 10 / 10 + 3 / 10 ) =
- ( 1 + 3 / 10 ) = - 1 3/10
Answer A
6 3/5 - ( -2 1/5 ) = 6 + 2 1/5=
6 + 2 + 3 / 5 + 1 / 5 = 8 4/5
#3D is correct if you meant -3 1/5
To solve these arithmetic problems, we will need to perform addition and subtraction operations with fractions and mixed numbers. Here's a step-by-step explanation for each problem:
Problem 1: (-1/2) + (1/3)
To add these fractions, we need a common denominator. The common denominator in this case is 6. We can convert -1/2 to -3/6 and 1/3 to 2/6.
So, (-3/6) + (2/6) = -1/6
Therefore, the answer is option A: -1/6.
Problem 2: (-3 5/1) + (-6 1/2)
To add these mixed numbers, we first need to convert them into improper fractions.
(-3 5/1) can be written as (-3 * 1 + 5)/1 = -15/1 + 5/1 = -15/1 + 5/1 = -10/1
(-6 1/2) can be written as (-6 * 2 + 1)/2 = -12/2 + 1/2 = -12/2 + 1/2 = -11/2
Now, let's add these fractions: (-10/1) + (-11/2)
To add fractions with different denominators, we need a common denominator, which in this case is 2. Multiply the numerator and denominator of -10/1 by 2 to get -20/2.
So, (-20/2) + (-11/2) = -31/2
Now, we need to express this fraction as a mixed number. Divide the numerator by the denominator: -31 ÷ 2 = -15 remainder 1.
The mixed number form of -31/2 is -15 1/2.
Therefore, the answer is option B: -3 7/10.
Problem 3: (5/8) - (-2/8)
To subtract these fractions, we can change the subtraction sign to addition and change the sign of the second fraction. So, (5/8) + (2/8) = 7/8.
Therefore, the answer is option D: 7/8.
Problem 4: (-9/10) - (2/5)
To subtract these fractions, we need a common denominator. The common denominator in this case is 10. We can convert -9/10 to -9/10 and 2/5 to 4/10.
So, (-9/10) - (4/10) = -13/10
Now, we need to express this fraction as a mixed number. Divide the numerator by the denominator: -13 ÷ 10 = -1 remainder 3.
The mixed number form of -13/10 is -1 3/10.
Therefore, the answer is option A: -1 3/10.
Problem 5: (6 3/5) - (-2 1/5)
To subtract these mixed numbers, we first need to convert them into improper fractions.
(6 3/5) can be written as (6 * 5 + 3)/5 = 33/5
(-2 1/5) can be written as (-2 * 5 + 1)/5 = -9/5
Now, let's subtract these fractions: (33/5) - (-9/5)
To subtract fractions with the same denominator, we can directly subtract the numerators. So, (33 - (-9))/5 = (33 + 9)/5 = 42/5 = 8 2/5
Therefore, the answer is option C: 8 2/5.
I hope this explanation helps you solve these problems!