18.
In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.
a. Find the percent of increase in the newspaper’s circulation from 2000 to 2001 and from 2001 to 2002.
b. Which period had a higher percent of increase, 2000 to 2001, or 2001 to 2002?
or, 3640/3250 = 1.12 for a 12% increase
looks good.
(3640 - 3250) / 3250 = 390 / 3250 = 39 / 325 = 3 / 25 = 12%
(4100 - 3640) / 3640 = 460 / 3640 = 46 / 364 = 23 / 182 = 12.637...%
The largest change came from 2001 to 2002.
my answer
Thank you
To find the percent increase in the newspaper's circulation from one year to another, you can use the following formula:
Percent Increase = ((New Value - Old Value) / Old Value) * 100
Now let's apply this formula to answer the questions:
a. Find the percent of increase in the newspaper's circulation from 2000 to 2001 and from 2001 to 2002.
To find the percent increase from 2000 to 2001:
Old Value = 3,250
New Value = 3,640
Percent Increase = ((3,640 - 3,250) / 3,250) * 100
Using a calculator, you can calculate:
Percent Increase = ((390) / 3,250) * 100
Percent Increase = (0.12) * 100
Percent Increase = 12%
Therefore, the percent increase in the newspaper's circulation from 2000 to 2001 is 12%.
To find the percent increase from 2001 to 2002:
Old Value = 3,640
New Value = 4,100
Percent Increase = ((4,100 - 3,640) / 3,640) * 100
Using a calculator, you can calculate:
Percent Increase = ((460) / 3,640) * 100
Percent Increase = (0.126) * 100
Percent Increase = 12.6%
Therefore, the percent increase in the newspaper's circulation from 2001 to 2002 is 12.6%.
b. Which period had a higher percent of increase, 2000 to 2001, or 2001 to 2002?
Comparing the results, we can see that the percent increase in the newspaper's circulation from 2001 to 2002 (12.6%) is higher than the percent increase from 2000 to 2001 (12%). Therefore, the period from 2001 to 2002 had a higher percent increase.