Analysis of a compound yields the following percentage composition.65.03 of Ag;15.68Cr;19.29 O. the simplest formula of the compound is?

To determine the simplest formula of a compound, we need to find the empirical formula. The empirical formula represents the simplest whole-number ratio of atoms in a compound.

To find the empirical formula, we need to calculate the moles of each element present in the compound.

First, let's calculate the moles of silver (Ag):
Molar mass of Ag = 107.87 g/mol
Moles of Ag = percentage of Ag / molar mass of Ag
Moles of Ag = 65.03 g / 107.87 g/mol
Moles of Ag ≈ 0.602 mol

Next, let's calculate the moles of chromium (Cr):
Molar mass of Cr = 52.00 g/mol
Moles of Cr = percentage of Cr / molar mass of Cr
Moles of Cr = 15.68 g / 52.00 g/mol
Moles of Cr ≈ 0.301 mol

Finally, let's calculate the moles of oxygen (O):
Molar mass of O = 16.00 g/mol
Moles of O = percentage of O / molar mass of O
Moles of O = 19.29 g / 16.00 g/mol
Moles of O ≈ 1.206 mol

Now, we have the moles of each element: Ag:Cr:O ≈ 0.602:0.301:1.206

To find the simplest whole-number ratio, we divide each value by the smallest value (in this case, 0.301):
Ag:Cr:O ≈ 0.602/0.301 : 0.301/0.301 : 1.206/0.301
Ag:Cr:O ≈ 2 : 1 : 4

The empirical formula of the compound is Ag2CrO4.

divide each by atomic numbers of each element.

You have now three new numbers. Divide them all by the lowest of the three: That is the atomic ratio in the formula.