5 kg of water at 40 degree Celsius is poured on a large block of ice at 0 degree celsius. How much ice melts?

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Please help me solve

To determine how much ice melts, we need to calculate the heat absorbed by the ice in order to raise its temperature to the melting point, and then the heat required to melt the ice completely.

First, we'll calculate the heat absorbed by the ice to reach 0 degrees Celsius:
The specific heat capacity of ice is 2.09 J/g°C.
Let's assume the mass of ice that melts is "m" grams.
The temperature change required is 0 - (-10) = 10 degrees Celsius.

So, the heat absorbed by the ice to reach 0 degrees Celsius is:
Q1 = (m grams) * (2.09 J/g°C) * (10°C)

Next, we'll calculate the heat required to melt the ice:
The heat of fusion for ice is 334 J/g.
The mass of ice that melts will be the same as the mass of water poured on it, which is 5 kg.

So, the heat required to melt the ice is:
Q2 = (5,000 grams) * (334 J/g)

Adding the two heat quantities together will give us the total heat required:
Total Heat = Q1 + Q2

Finally, we'll substitute the values and calculate:

Total Heat = (m grams) * (2.09 J/g°C) * (10°C) + (5,000 grams) * (334 J/g)

Since we don't know the value of "m" grams, we cannot determine exactly how much ice melts without more information. However, once we have the value for "m", we can solve for it using the equation mentioned above.