Ms. Sue please I need help with these two problems!
Tell whether the given number is a solution of each question
5b+1=16; -3
14=1/3x+5;27
One of these answers is right.
Please post your work to show how you think these problems should be solved. I'll be glad to check them.
well, if it is actually
14 = (1/3) x + 5
or
14 = (x/3)+ 5
then that is
14 = (1/3)27 + 5
14 = 9 + 5 yes
however
14 is not 1/ (3*27) + 5
5b+1=16; -3 is wrong because 5*(-3)=(-15)+1 would equal -14. Question number two would be correct then. Am I correct Ms. Sue?
Yes, you're right.
Damon must have missed the minus sign.
Thank you Ms. Sue!
I did not miss a sign. 1/3x is not x/3
I'm sorry, Damon. I was looking at # 1 instead of # 2.
xd funny
I'd be happy to help you with these problems! Let's go through each question step by step and determine whether the given number is a solution.
1. 5b + 1 = 16; -3
To check if -3 is a solution, we need to substitute -3 for b in the equation and see if it satisfies the equation.
Substituting -3 for b, we get:
5(-3) + 1 = 16
-15 + 1 = 16
-14 = 16
Since -14 is not equal to 16, we can conclude that -3 is not a solution to this equation.
2. 14 = (1/3)x + 5; 27
Similarly, we need to substitute 27 for x in the equation and see if it satisfies the equation.
Substituting 27 for x, we get:
14 = (1/3)(27) + 5
14 = 9 + 5
14 = 14
Since 14 is equal to 14, we can conclude that 27 is a solution to this equation.
So, to summarize:
-3 is not a solution to the equation 5b + 1 = 16.
27 is a solution to the equation 14 = (1/3)x + 5.