Question

dy/dx+2y=sinx,

The answer is:1/5(2sinx+cosx)+ce^-2x

Answer 1

well, you know that the solution to

y' + 2y = 0

is

y = c e^(-2x)

Now just come up with the other part. Besides your class text, take a look at a similar problem here:

https://au.answers.yahoo.com/question/index?qid=20100317130334AAtWVqs