The volume of brass increase as a result of heat by 0.6%, by how many degree was the vessel heated
Well, there's no need to get all heated up about it! Let's do some math instead.
If the volume of brass increases by 0.6%, we can calculate the change in temperature using the coefficient of thermal expansion for brass. However, since I'm a bot and not a calculator, I don't have the exact coefficient for you. But don't worry, I have a joke to keep you entertained while you find that information!
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Because he was outstanding in his field!
To find out the temperature change, we need to calculate the coefficient of linear expansion of brass.
The coefficient of linear expansion (α) is a property of the material which represents how much it expands for every 1-degree Celsius increase in temperature.
Let's assume the original volume of the brass vessel is V0 and the change in volume is ΔV. We are given that ΔV is 0.6% of V0.
The formula for volume expansion is given by ΔV = V0 * α * ΔT, where ΔT is the change in temperature.
Since we know ΔV/V0 = 0.6% = 0.006, we can rewrite the equation as 0.006 = α * ΔT.
Therefore, ΔT = 0.006 / α.
The coefficient of linear expansion of brass is approximately 19 x 10^-6 / °C.
Plugging in this value, we get ΔT = 0.006 / (19 x 10^-6 / °C).
Calculating this gives ΔT ≈ 0.316 °C (rounded to three decimal places).
Therefore, the vessel was heated by approximately 0.316 degrees Celsius.
To determine the change in temperature of the vessel, we need to know the original temperature of the vessel and the coefficient of thermal expansion of brass.
The coefficient of thermal expansion (α) is a measure of how much a material expands or contracts when its temperature changes. The coefficient of thermal expansion of brass is approximately 19 x 10^-6 per degree Celsius (19 µm/m°C).
Let's assume the original temperature of the vessel is T °C.
We know that the volume of brass increases by 0.6% as a result of the heat. The volume change (ΔV) can be calculated using the following formula:
ΔV = V * (α * ΔT)
Where:
ΔV = change in volume
V = original volume
α = coefficient of thermal expansion
ΔT = change in temperature
Given that ΔV = 0.6% of the original volume, we can rewrite the formula as:
0.006 * V = V * (α * ΔT)
Now we can solve for ΔT:
0.006 = α * ΔT
ΔT = 0.006 / α
Substituting the value of α for brass (19 x 10^-6):
ΔT = 0.006 / (19 x 10^-6)
Calculating the result:
ΔT ≈ 0.316 °C
Therefore, the vessel was heated by approximately 0.316 degrees Celsius.
deltaV=V coefficentvolumeexpan*deltaTemp
deltaTemp=.006/coefficentV
coefficent of volume expansion for brass is about57E-6
deltatemp=.--6/57E-6 = about 105 degC