what weight of NaCl is needed to prepare 200mls of a 250ppm Na solution?
WEll, the mass of 200ml is 200grams.
massNaCl=250E-6 * 200grams=.05grams
check my work.
working not really clear. can you please explain further.
To determine the weight of NaCl needed to prepare a 200ml solution with a concentration of 250ppm (parts per million) of Na, we need to understand how ppm is measured and calculate it.
The term "ppm" represents the concentration of a substance within a solution. It is equivalent to 1 gram per 1 million grams of solution, which can also be interpreted as 1 milligram per 1 liter of solution.
To calculate the weight of NaCl needed, we follow these steps:
Step 1: Convert the desired concentration from ppm to a decimal fraction:
Since 1ppm = 1mg/L, we convert 250ppm to (250/1,000) = 0.25mg/L or 0.25 mg/ml.
Step 2: Convert the solution volume from milliliters (ml) to liters (L):
Since 1L = 1,000ml, we convert 200ml to (200/1,000) = 0.2L.
Step 3: Calculate the weight of NaCl needed:
The weight of NaCl (in grams) is equal to the concentration (in mg/ml) multiplied by the volume (in L):
Weight of NaCl = concentration x volume
Weight of NaCl = 0.25 mg/ml x 0.2 L
Weight of NaCl = 0.05 grams (or 50 milligrams)
Therefore, to prepare a 200ml solution with a concentration of 250ppm Na, you would need 0.05 grams (or 50 milligrams) of NaCl.