a 50 kg ice skater is skating on a frozen lake where the ice has a coefficient of friction of .08. How much force is required to push her across the ice at a constant velocity?

.08 * 60 * 9.81 Newtons

To calculate the force required to push the ice skater across the ice at a constant velocity, you can use the equation:

Force = coefficient of friction × Normal force

First, we need to determine the normal force acting on the skater. The normal force is equal to the weight of the skater, which can be calculated using the formula:

Weight = mass × acceleration due to gravity

Given that the mass of the skater is 50 kg and the acceleration due to gravity is approximately 9.8 m/s²:

Weight = 50 kg × 9.8 m/s² = 490 N

Now, we can calculate the force required:

Force = coefficient of friction × Normal force
= 0.08 × 490 N
= 39.2 N

Therefore, a force of 39.2 Newtons is required to push the 50 kg ice skater across the ice at a constant velocity.

To calculate the force required to push the ice skater across the ice at a constant velocity, you need to use Newton's second law of motion, which states that force equals mass multiplied by acceleration.

First, let's determine the acceleration of the ice skater. Since she is moving at a constant velocity, her acceleration is zero because there is no change in her speed or direction.

Next, we can calculate the force using the formula F = m × a, where F is the force, m is the mass, and a is the acceleration. In this case, since the acceleration is zero, the force required to push the skater at constant velocity is also zero.

Therefore, no force is required to push the ice skater across the ice at a constant velocity.