From the four corners of a square piece of paper of side 12cm, small squares of 1cm are cut off. The edges of this are bent up and joined to form a container of height 1cm. What is the capacity of the container? If squares of side 2cm are cut off, what would be the capacity?

Oh, cutting squares and bending paper! Sounds like we're combining arts and crafts with a splash of math. I'm ready to clown around and help you out!

In the first scenario, we are cutting off small squares of 1cm from each corner, which means the length and width of the base of the container will be reduced by 2cm. So, the new dimensions of the base will be 10cm by 10cm. Since the height of the container is 1cm, we can calculate its capacity by using the formula: capacity = length x width x height.

Therefore, the capacity of the container when cutting squares of side 1cm would be:
Capacity = 10cm x 10cm x 1cm = 100cm³.

Now let's spice things up and cut squares of side 2cm. This time, the length and width of the base will be reduced by 4cm, leaving us with a base measuring 8cm by 8cm. We'll use the same formula to determine the capacity.

Hence, the capacity of the container when cutting squares of side 2cm would be:
Capacity = 8cm x 8cm x 1cm = 64cm³.

Voila! You now have the capacity for both scenarios. Just remember, no matter how much paper you cut, I'm here to entertain you with my clowning antics!

To find the capacity of the container, we need to calculate the volume.

1) When small squares of side 1cm are cut off:
- We are left with a square piece of paper with sides measuring 12-2 = 10cm.
- The height of the container is 1cm.
- So, the volume is given by V = length x width x height = 10cm x 10cm x 1cm = 100cm³.

Therefore, the capacity of the container when cutting off squares of side 1cm is 100cm³.

2) When small squares of side 2cm are cut off:
- We are left with a square piece of paper with sides measuring 12-4 = 8cm.
- The height of the container is 1cm.
- So, the volume is V = length x width x height = 8cm x 8cm x 1cm = 64cm³.

Therefore, the capacity of the container when cutting off squares of side 2cm is 64cm³.

To find the capacity of the container, we need to calculate the volume of the container.

First, let's consider the case where small squares of side 1cm are cut off.

The original square piece of paper has a side length of 12cm, so its area is 12cm x 12cm = 144cm^2.

When four 1cm squares are cut off from the corners, the remaining piece of paper has sides measuring (12cm - 1cm - 1cm) = 10cm. Thus, the base area of the container is 10cm x 10cm = 100cm^2.

The height of the container is given as 1cm.

Therefore, the volume of the container can be calculated as:
Volume = Base Area x Height = 100cm^2 x 1cm = 100cm^3.

So, the capacity of the container when small squares of side 1cm are cut off is 100cm^3.

Now, let's consider the case where small squares of side 2cm are cut off.

When four 2cm squares are cut off from the corners, the remaining piece of paper has sides measuring (12cm - 2cm - 2cm) = 8cm. Thus, the base area of the container is 8cm x 8cm = 64cm^2.

Again, the height of the container is given as 1cm.

Therefore, the volume of the container when small squares of side 2cm are cut off can be calculated as:
Volume = Base Area x Height = 64cm^2 x 1cm = 64cm^3.

So, the capacity of the container when small squares of side 2cm are cut off is 64cm^3.

But I am not getting the 2nd one

so the base will be 10 cm by 10 cm by 1 cm.

(you are cutting of 1 cm from either end of the 12)

Volume = (10)(10)(1) cm^3 = 100 cm^3

follow the same steps for the second part.