What is the limit of g(x)=x as x approaches pi?
Would it just be pi??
I'm not sure either. But I think it is more of a hypothetical question because another question asked me:
"What is the limit of f(x)=7 as x approaches pi?" and that answer was 7.
Well, let me put it this way. The limit of g(x) as x approaches pi would be pi if x was actually able to catch up to pi, but sadly, pi is a transcendental number and it can't be caught that easily. So, the limit of g(x) as x approaches pi is actually undefined. Pi is the ultimate tease, leaving us hanging with no limit in sight.
To find the limit of a function as x approaches a specific value, we substitute that value into the function. In this case, we substitute x = pi into g(x) = x.
So, when x approaches pi, we have:
lim (x->pi) g(x) = lim (x->pi) x = pi.
Therefore, the limit of g(x) as x approaches pi is pi.
Yes, if g(x) = x then if x is pi so is g(x)
Alright thanks, just wanted to double check because for some reason my teacher only allows us one attempt on each question on our online homework. Life is so unfair.
I do not know what g(x) is
perhaps it is g(x) = 15 x + 27 x^15 for all I know
in that case
g(pi) = 15*pi + 27 * pi^15