A solution is created using 2.1700 grams of Calcium Hydroxide (MW is 74.093) in a 1L volumetric flask. A 50 mL aliquot is then taken and aded to a 350 mL volumteric flask and filled to the line. Finally, a 10 aliquot of the that solution is taken and added to a 100 mL volumetric flask and diluted to the line. What is the concentration of OH ion in the final solution in mol/L? (answer to 4 decimal places)

To find the concentration of OH ion in the final solution, we need to calculate the number of moles of OH ion present in the solution and then divide it by the volume of the solution.

Let's break down the steps:

Step 1: Calculate the number of moles of Ca(OH)2 in the 2.1700 grams of the original solution.
Divide the mass of Ca(OH)2 by its molar mass:
Number of moles = Mass / Molar mass = 2.1700 g / 74.093 g/mol

Step 2: Calculate the number of moles of OH ion in the 50 mL aliquot.
The molar ratio between Ca(OH)2 and OH ion is 1:2 (there are two OH ions for every Ca(OH)2 molecule):
Number of moles of OH ion in the aliquot (50 mL) = (Number of moles of Ca(OH)2) * (2 moles of OH ions / 1 mole of Ca(OH)2)

Step 3: Calculate the concentration of OH ion in the 50 mL aliquot.
Concentration of OH ion = (Number of moles of OH ion) / (Volume of aliquot in liters) = (Number of moles of OH ion) / (50 mL * 0.001 L/mL)

Step 4: Calculate the number of moles of OH ion in the 10 mL aliquot from the previous step.
The molar ratio between the 50 mL aliquot and the 10 mL aliquot is 1:5 since 50 mL / 10 mL = 5. So, multiply the number of moles of OH ion in the 50 mL aliquot by 5.

Step 5: Calculate the concentration of OH ion in the 10 mL aliquot.
Concentration of OH ion = (Number of moles of OH ion) / (Volume of aliquot in liters) = (Number of moles of OH ion) / (10 mL * 0.001 L/mL)

The concentration of OH ion in the final solution is the same as in the 10 mL aliquot since the solution was diluted to the line.

Perform these calculations to find the concentration of OH ion in mol/L.