calculate the weight of co2 by complete combustion of 1.5 \g of ethane
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To calculate the weight of CO2 produced by complete combustion of ethane, we need to consider the balanced chemical equation for the combustion of ethane:
C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O
According to the equation, one mole of ethane (C2H6) reacts with seven halves (7/2) moles of oxygen gas (O2) to produce two moles of carbon dioxide (CO2) and three moles of water (H2O).
Step 1: Determine the molar mass of ethane (C2H6):
Carbon (C) has a molar mass of 12.01 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Ethane (C2H6) consists of 2 carbon atoms and 6 hydrogen atoms.
Molar mass of C2H6 = (2 * 12.01 g/mol) + (6 * 1.01 g/mol)
= 24.02 g/mol + 6.06 g/mol
= 30.08 g/mol
Step 2: Calculate the moles of ethane:
Given that you have 1.5 g of ethane, we can use the equation:
moles of ethane = mass of ethane / molar mass of ethane
= 1.5 g / 30.08 g/mol
≈ 0.050 mol
Step 3: Determine the moles of CO2 produced:
From the balanced equation, we know that 1 mole of ethane produces 2 moles of carbon dioxide. Therefore, we can calculate the moles of CO2 produced:
moles of CO2 = 2 * moles of ethane
= 2 * 0.050 mol
= 0.100 mol
Step 4: Calculate the weight of CO2 produced:
To find the weight of CO2, we need to multiply the moles of CO2 by its molar mass:
Molar mass of CO2 = atomic mass of carbon + (2 * atomic mass of oxygen)
= 12.01 g/mol + (2 * 16.00 g/mol)
= 44.01 g/mol
weight of CO2 = moles of CO2 * molar mass of CO2
= 0.100 mol * 44.01 g/mol
= 4.40 g
Therefore, the weight of CO2 produced by the complete combustion of 1.5 g of ethane is approximately 4.40 g.
To calculate the weight of CO2 produced by the complete combustion of 1.5 g of ethane, we need to use the balanced chemical equation and the molar masses of the compounds involved.
First, let's write the balanced chemical equation for the combustion of ethane (C2H6):
C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O
From this equation, we can see that for every 1 molecule of ethane combusted, 2 molecules of CO2 are produced.
Next, we need to calculate the molar mass of ethane (C2H6). The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of hydrogen (H) is 1.01 g/mol. Since ethane has 2 carbon atoms and 6 hydrogen atoms, the molar mass of ethane is:
(2 * 12.01 g/mol) + (6 * 1.01 g/mol) = 30.07 g/mol
Now, we can calculate the moles of ethane in 1.5 g by dividing the given mass by the molar mass:
moles of ethane = 1.5 g / 30.07 g/mol ≈ 0.05 mol
Since 2 moles of CO2 are produced for every 1 mole of ethane, the number of moles of CO2 produced can be calculated using the mole ratio:
moles of CO2 = 2 * moles of ethane ≈ 2 * 0.05 mol = 0.10 mol
Finally, we can calculate the weight of CO2 produced by multiplying the moles of CO2 by its molar mass. The molar mass of CO2 is 44.01 g/mol (12.01 g for each carbon atom and 16.00 g for each oxygen atom):
weight of CO2 = moles of CO2 * molar mass of CO2 = 0.10 mol * 44.01 g/mol ≈ 4.40 g
Therefore, the weight of CO2 produced by the complete combustion of 1.5 g of ethane is approximately 4.40 g.
2C2H6 + 7O2 ==> 4CO2 + 6H2O
mols C2H6 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols C2H6 to mols CO2. That is
?mols C2H6 x (7 mols O2/2 mols C2H6) = ? = ?
Now convert mols CO2 to grams. g CO2 = mols CO2 x molar mass CO2 = ?