A net force is applied to an object, the same net force is then applied to a second object with 6.2 times the mass of the first then the acceleration of the second object will be how many times the acceleration of the first object?
F=ma, so a = F/m
so, greater mass, less acceleration
To determine the relationship between the accelerations of the two objects, we can make use of Newton's second law of motion. According to this law, the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.
Let's denote the mass of the first object as m₁ and its acceleration as a₁. The mass of the second object is given as 6.2 times the mass of the first object, so we can write it as 6.2m₁. The net force applied is the same for both objects.
Newton's second law can be written as:
F = m₁a₁ (Equation 1)
F = (6.2m₁)a₂ (Equation 2)
Since the net force is the same in both cases, we can equate the expressions for F from both equations:
m₁a₁ = 6.2m₁a₂
Now, we can divide both sides of the equation by m₁ to simplify:
a₁ = 6.2a₂
Therefore, the acceleration of the second object (a₂) will be 1/6.2 (approximately 0.161) times the acceleration of the first object (a₁).
In summary, the acceleration of the second object will be approximately 0.161 times the acceleration of the first object.