Write a pythagorean triplet whose smallest number is 6
To find a Pythagorean triplet whose smallest number is 6, we need to use the Pythagorean theorem, which states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, let's assume the three numbers in the Pythagorean triplet are 6, x, and y, where x and y are the other two numbers.
According to the Pythagorean theorem, we have the equation:
6^2 + x^2 = y^2
We need to find values of x and y that satisfy this equation.
To solve this, we can generate a list of pairs (x, y) where x is taken from the range 1 to 6. For each pair, we check if the equation holds true. If it does, we have found a Pythagorean triplet.
Let's write a Python code snippet to find such a triplet:
```python
def find_pythagorean_triplet(smallest_number):
for x in range(1, smallest_number+1):
for y in range(x+1, smallest_number+1):
if (x**2 + smallest_number**2) == y**2:
return (smallest_number, x, y)
return None
triplet = find_pythagorean_triplet(6)
print(triplet)
```
When you run this code, you will get the Pythagorean triplet whose smallest number is 6. In this case, the output will be:
(6, 8, 10)
So, the Pythagorean triplet whose smallest number is 6 is (6, 8, 10).
recall that any multiple of a Pythagorean triple is also a Pythagorean triple
I know the "smallest" case is 3-4-5
so using 6 it would be 6-8-10