A line passes through the points (1, 5) and (-2, -4). What is the sum of twice the slope and the y-intercept of the line?I got y=3x+2 and the answer is 10
assuming you have to double both the slope and y-intercept, you are CORRECT (the question's wording wasn't overtly clear)
it says 10 is wrong
then you could try 8, if the question is asking you to only double the slope
yup its 8 ty
To find the equation of the line passing through two points, you can start by calculating the slope of the line using the formula:
slope (m) = (y2 - y1) / (x2 - x1)
Given the two points (1, 5) and (-2, -4), you can substitute the coordinates into the slope formula:
m = (-4 - 5) / (-2 - 1) = -9 / -3 = 3
Now that you have the slope (m), you can find the y-intercept (b) of the line using the formula y = mx + b. Substitute one of the known points and the slope into the equation:
5 = 3(1) + b
5 = 3 + b
b = 5 - 3
b = 2
So, the equation of the line is y = 3x + 2. Now, to calculate the sum of twice the slope and the y-intercept:
2*(slope) + y-intercept = 2*(3) + 2 = 6 + 2 = 8
Therefore, the correct sum of twice the slope and the y-intercept is 8, not 10.