Integrate it step by step using inverse trigonometric functions.
∫(4/(4-5x))dx
why complicate things?
wouldn't that just be
∫(4/(4-5x))dx
= 4∫(1/(4-5x))dx
= 4(-1/5) ln(4-5x) + c
= (-4/5) ln(4-5x) + c
∫(4/(4-5x))dx
wouldn't that just be
∫(4/(4-5x))dx
= 4∫(1/(4-5x))dx
= 4(-1/5) ln(4-5x) + c
= (-4/5) ln(4-5x) + c