write all possible 3 digit numbers the sum of whose digits is 4.
103
(1+ 0 + 3 = 4)
Any combination/order you write will work.
112
(1+1+2=4)
Any combination/order you write will work.
220
(2+2+0=4)
Any combination/order you write will work.
400
(4+0+0=4)
Only this combination/order will work.
You should have a total of 10 numbers.
Try listing them all here.
Typo:
For any combination, 0 cannot be the first number.
To find all possible 3-digit numbers whose digits sum up to 4, we can use a step-by-step approach.
Step 1: Start with the smallest digit being 0 and the largest digit being 9 since we are looking for 3-digit numbers.
Step 2: Determine the value of the first digit. Since the sum of all digits is 4, the first digit can be any number from 1 to 4, inclusive.
Step 3: Determine the value of the second digit. The second digit can be any number from 0 to 4, inclusive, to ensure the sum of the first two digits is less than or equal to 4.
Step 4: Determine the value of the third digit. The third digit can be any number from 0 to 4, inclusive, to ensure the sum of all three digits is exactly 4.
Using this approach, we can write down the possible 3-digit numbers:
104
113
122
131
140
203
212
221
230
302
311
320
401
410
Therefore, these are all the possible 3-digit numbers whose digits sum up to 4.
To find all possible three-digit numbers whose digits sum up to 4, we can start by considering the possible values for each digit.
Let's denote the digits as A, B, and C, where A is the hundreds digit, B is the tens digit, and C is the units digit.
Since the sum of the three digits is 4, we have the equation A + B + C = 4.
Now, we can consider all possible values for A, B, and C, while ensuring the equation holds true.
One way to find all the possible combinations is to use a systematic approach.
Let's explore the options:
1. A = 1:
If A = 1, then B + C = 3
Possible combinations for B and C are: B = 2, C = 1; B = 1, C = 2; B = 3, C = 0; B = 0, C = 3.
2. A = 2:
If A = 2, then B + C = 2
Possible combinations for B and C are: B = 2, C = 0; B = 1, C = 1; B = 0, C = 2.
3. A = 3:
If A = 3, then B + C = 1
Possible combinations for B and C are: B = 1, C = 0; B = 0, C = 1.
Therefore, the possible three-digit numbers whose digits sum up to 4 are:
102, 120, 201, 210, 300, 030, 003, 021, 012, 111, 022, 202.
Hence, there are 12 possible three-digit numbers that meet the given criteria.