it takes 3 mins to fill a water tank using pipe A and 5 mins to fill the same tank using pipe b alone how long will it take to fill the water if pipes a and b are used together, in minutes and seconds?
T = t1*t2/(t1+t2) = 3*5/(3+5) = 1.875 Min. = 1 min, and 52.5 Sec.
To find out how long it will take to fill the water tank when both pipes A and B are used together, you can use the concept of "work per unit time."
Let's assume that the tank has a capacity of 1 unit (the actual value of the capacity doesn't matter, as long as we maintain consistency).
Pipe A fills the tank in 3 minutes, which means it fills 1/3 of the tank in 1 minute.
Pipe B fills the tank in 5 minutes, which means it fills 1/5 of the tank in 1 minute.
When both pipes A and B are used together, their filling rates are additive. Therefore, the combined filling rate when both pipes are used is 1/3 + 1/5 = 8/15 of the tank filled in 1 minute.
Now, to find out how long it will take to fill the tank when both pipes A and B are used together, we can calculate the reciprocal of the filling rate (time per unit).
The reciprocal of 8/15 is 15/8. Therefore, it will take 15/8 minutes to fill the water tank when both pipes A and B are used together.
To convert this time into minutes and seconds, we need to perform some arithmetic:
15/8 minutes is equal to 15 minutes divided by 8.
Dividing 15 by 8, we get the quotient 1 and the remainder 7.
So, the tank will be filled in 1 minute and 7/8 (or 0.875) minutes when both pipes A and B are used together.
Converting 0.875 minutes to seconds, we multiply it by 60 since there are 60 seconds in one minute.
0.875 * 60 = 52.5 seconds.
Therefore, it will take approximately 1 minute and 52.5 seconds to fill the water tank when pipes A and B are used together.