Block A (Mass = 3.500 kg) and Block B (Mass = 2.450 kg) are attached by a massless string Block A sits on a horizontal tabletop. There is friction between the surface and Block A. The string passes overa frictionless, massless pulley. Block B hangs down vertically as shown. When the two blocks are released, Block B accelerates downward at a rate of 2.550 m/s2. What is the tension in the string?

f = m a

m g - t = m a

t = m g - m a = m (g - a)

t = 2.45 (9.80 - 2.55)

answer units are Newtons

To find the tension in the string between Block A and Block B, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

In this case, Block B is accelerating downward, so there must be a net force acting on it. The force causing this acceleration is the tension in the string.

First, we need to determine the mass of Block B. We are given that the mass of Block A is 3.500 kg, and the mass of Block B is 2.450 kg.

Next, we can calculate the net force on Block B. The net force is equal to the mass of Block B multiplied by its acceleration.

Net Force = Mass × Acceleration
Net Force = 2.450 kg × 2.550 m/s^2

Now we can find the tension in the string. Since Block A and Block B are connected by the string and are accelerating together, the tension in the string will be the same for both blocks.

Therefore, the tension in the string is equal to the net force on Block B.

Tension = Net Force
Tension = 2.450 kg × 2.550 m/s^2

Solving this equation will give us the tension in the string.