84cubic centimeters of hydrogen chloride gas measured at s.t.p is dissolved in water and titrated with 0.15M sodium hydroxide.What volume of sodium hydroxide solution is required for complete neutralization?

(0.084/22.4)= (0.15)V ... solve for V

To find the volume of sodium hydroxide solution required for complete neutralization, you need to determine the stoichiometry of the reaction between hydrogen chloride (HCl) and sodium hydroxide (NaOH).

The balanced chemical equation for the neutralization reaction between HCl and NaOH is:
HCl + NaOH -> NaCl + H2O

According to the stoichiometry of the equation, 1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of NaCl and 1 mole of H2O. This means that the mole ratio of HCl to NaOH is 1:1.

To calculate the number of moles of HCl, you need to use the ideal gas law at standard temperature and pressure (STP):
PV = nRT

Given that the volume of HCl gas is 84 cubic centimeters (cm³) at STP, which is equivalent to 84 milliliters (mL), and the molar volume of any ideal gas at STP is 22.4 liters per mole (L/mol), we can convert the volume of HCl to moles using the following equation:

n = V / Vm

n = 84 mL / 22.4 L/mol
n = 0.00375 mol

Since the mole ratio of HCl to NaOH is 1:1, the number of moles of NaOH required for neutralization is also 0.00375 mol.

To determine the volume of the sodium hydroxide solution required, we can use the following equation:

n = C × V

Where:
n = number of moles
C = molar concentration (0.15 M)
V = volume (unknown)

Rearranging the equation:

V = n / C
V = 0.00375 mol / 0.15 mol/L
V = 0.025 L or 25 mL

Therefore, 25 mL of the 0.15 M sodium hydroxide solution is required for the complete neutralization of 84 cm³ of hydrogen chloride gas at STP.