A car is traveling along a straight road at a velocity of +35.1 m/s when its engine cuts out. For the next 1.95 seconds, the car slows down, and its average acceleration is . For the next 6.52 seconds, the car slows down further, and its average acceleration is . The velocity of the car at the end of the 8.47-second period is +23.6 m/s. The ratio of the average acceleration values is = 1.25. Find the velocity of the car at the end of the initial 1.95-second interval.

dont even know where to start

To find the velocity of the car at the end of the initial 1.95-second interval, we can use the following equation:

v = u + at

Where:
v = final velocity
u = initial velocity
a = acceleration
t = time

In the given problem, some of the quantities are given, while others are unknown. Let's first list down the given quantities:

Initial velocity (u) = +35.1 m/s (positive sign indicates the direction)
Time (t1) = 1.95 seconds
Final velocity (v1) = Unknown

Now, let's calculate the average acceleration during the first interval using the given ratio:

Average acceleration (a1) / Average acceleration (a2) = 1.25

Let's assume the first average acceleration is a1, and the second average acceleration is a2.

Therefore, a1 / a2 = 1.25

Now, let's determine the individual accelerations:

Average acceleration (a1) = a2 * 1.25

While the individual values of a1 and a2 are unknown, we can denote them with variables for now.

Using these values, we can calculate the final velocity (v1) using the equation mentioned above. Plug in the values we have:

v1 = u + (a1 * t1)

Substituting the known values:

v1 = +35.1 m/s + (a1 * 1.95 seconds)

The goal is to find the value of v1.

To proceed further, we would need the specific values of a1 and a2. These values are missing from the problem statement. Without them, it is not possible to calculate the final velocity at the end of the initial 1.95-second interval.