A car traveling in a straight line has a velocity

of 3.7 m/s at some instant. After 7.99 s, its
velocity is 12.2 m/s.
What is its average acceleration in this time
interval?
Answer in units of m/s
2

So average acceleration is just the 'slope' of the velocity vs time graph..

The equation would be (Vf - V0)/t = average acceleration...

(12.2-3.7)/7.99 = 1.06 m/s^2 because the units are (m/s)/s

To find the average acceleration, we can use the formula:

Average acceleration = (change in velocity) / (time interval)

The change in velocity is given by:

Change in velocity = final velocity - initial velocity

Given that the initial velocity is 3.7 m/s and the final velocity is 12.2 m/s, the change in velocity is:

Change in velocity = 12.2 m/s - 3.7 m/s = 8.5 m/s

The time interval is given as 7.99 s.

Using the formula for average acceleration:

Average acceleration = (8.5 m/s) / (7.99 s) = 1.07 m/s^2

Therefore, the average acceleration of the car in this time interval is 1.07 m/s^2.

To find the average acceleration of the car, we can use the following formula:

Average acceleration = (Change in velocity) / (Time interval)

The change in velocity is the difference between the final velocity and the initial velocity:

Change in velocity = Final velocity - Initial velocity

Given that the initial velocity is 3.7 m/s and the final velocity is 12.2 m/s, we can calculate the change in velocity:

Change in velocity = 12.2 m/s - 3.7 m/s

Now we need to calculate the time interval. In this case, it is given as 7.99 seconds.

Finally, we can substitute the values into the formula to find the average acceleration:

Average acceleration = (12.2 m/s - 3.7 m/s) / 7.99 s

Simplifying the equation:

Average acceleration = 8.5 m/s / 7.99 s

Calculating the average acceleration:

Average acceleration ≈ 1.0638 m/s²

Therefore, the average acceleration of the car in this time interval is approximately 1.0638 m/s².