The temperature of a chemical compound was 1°C at 3:00 A.M. During a reaction, it dropped 3°C per minute until 3:13 A.M. What was the temperature at 3:13 A.M.?
13 minutes?
Tf=ti-13*1C
Tf=1C-13=-12C
To find the temperature at 3:13 A.M., we first need to determine the time duration between 3:00 A.M. and 3:13 A.M.
Step 1: Calculate the difference in minutes between 3:00 A.M. and 3:13 A.M.
To calculate the time difference, we subtract the starting time (3:00 A.M.) from the ending time (3:13 A.M.):
3:13 A.M. - 3:00 A.M. = 13 minutes.
Step 2: Determine the number of temperature drops during this time duration.
Since the temperature dropped 3 degrees Celsius per minute, we need to determine how many times it dropped in 13 minutes:
13 minutes / 1 minute (per drop) = 13 drops.
Step 3: Calculate the decrease in temperature.
The temperature decreased by 3°C per drop, and in this case, there were 13 drops, so the total decrease in temperature can be calculated as:
3°C/drop * 13 drops = 39°C.
Step 4: Determine the final temperature.
Since the temperature initially was 1°C, and it decreased by 39°C during the 13 minutes, we simply subtract the temperature decrease from the initial temperature:
1°C - 39°C = -38°C.
Therefore, the temperature at 3:13 A.M. was -38°C.
To find the temperature at 3:13 A.M., we need to determine the total decrease in temperature from 3:00 A.M. to 3:13 A.M.
First, let's calculate the time difference between 3:00 A.M. and 3:13 A.M.
Since there are 60 minutes in an hour, the time difference is 13 minutes.
Given that the temperature decreased by 3°C per minute, we can multiply the time difference by the rate of decrease to find the total temperature decrease.
Total temperature decrease = Rate of decrease * Time difference
= 3°C/min * 13 min
= 39°C
Now we subtract the total temperature decrease from the initial temperature at 3:00 A.M.
Final temperature = Initial temperature - Total temperature decrease
= 1°C - 39°C
= -38°C
Therefore, the temperature at 3:13 A.M. was -38°C.