The length and breadth of a park in the ratio 2:1 and its perimeter is 240 m. A path 2m wide runs inside it,along its boundary.Find the cost of paving the path at Rs 80 per square metre?
Your answer was wrong right answer was 37120 rupee
Wrong ans
To find the cost of paving the path, we first need to calculate the area of the path.
Let's assume the length of the park is 2x and the breadth is x (since the ratio of length to breadth is 2:1).
The perimeter of the park is given as 240 m, which is the sum of all four sides.
Perimeter of park = 2(length + breadth)
240 = 2(2x + x)
240 = 2(3x)
240 = 6x
x = 40 m
So, the length of the park is 2x = 2 * 40 = 80 m, and the breadth is x = 40 m.
Now, let's calculate the dimensions of the park including the path. Since the path is 2m wide running along the boundary, we need to increase each dimension by 4m (2m on each side).
Length of park including path = 80 + 4 + 4 = 88 m
Breadth of park including path = 40 + 4 + 4 = 48 m
Now, we can calculate the area of the path:
Area of path = (Length of park including path) * (Breadth of park including path) - (Length of park * Breadth of park)
Area of path = 88 * 48 - 80 * 40
Area of path = 4224 - 3200
Area of path = 1024 m²
Finally, we can find the cost of paving the path:
Cost of paving the path = Area of path * Cost per square metre
Cost of paving the path = 1024 * Rs 80
Cost of paving the path = Rs 81920
Therefore, the cost of paving the path at Rs 80 per square meter is Rs 81920.
Wrong
first find the dimensions
breath (width) ---- x
length ----------- 2x
2x + 4x = 240
6x = 240
x = 40
so the park is 40 m by 80 m
area of whole park = 3200 m^2
make a sketch to see that the area of the region inside the path is 36 m by 76 m
area of that part = 2736 m^2
so area of path = .... m^2
cost = 82(....)